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Suppose you choose a tile at random from a bag containing 2 a’s, 3 b,s, and 4c,s. You replace the first tile in the bag and the choose again. Find the probability p(a and b)

Respuesta :

Answer:4/27

Step-by-step explanation:

P(B)=3/9; P(C)=4/9

3 of the 9 tiles are B's and 4 out of 9 tiles are C's

P(B and C)= P(B) x P(C)

= 3/9 * 4/9 = 12/81 = 4/27

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