Respuesta :

caylus
Hello,
That's better.

I suppose [tex]y=( \sqrt{x} + \dfrac{1}{ \sqrt{x} } )^2 \\ y'=2*( \sqrt{x} + \dfrac{1}{ \sqrt{x} } )*( \dfrac{1}{2 \sqrt{x} } - \dfrac{3}{2x \sqrt{x} } )[/tex]

If x=2  then
[tex]y'=2*( \sqrt{2} + \dfrac{1}{ \sqrt{2} } )*( \dfrac{1}{2 \sqrt{2} } - \dfrac{3}{2*2* \sqrt{2} } )\\ =2* \dfrac{2+ \sqrt{2} }{ \sqrt{2} } * \dfrac{1}{4*\sqrt{2} } *(-1)\\ =- \dfrac{2+ \sqrt{2} }{4} [/tex]

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