The sculpture ‘Cubo Vazado’ [Emptied Cube] by the Brazilian artist Franz Weissmann is formed by removing cubical blocks from a solid cube to leave the symmetrical shape shown.
If all the edges have length 1, 2 or 3, what is the volume of the sculpture?

Respuesta :

Answer:

The volume of the sculpture is 12 cubic units

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Find the volume of the L-shaped figure

The volume is given by

[tex]V=Bh[/tex]

where

B is the area of the base

h is the height of the figure

we have

[tex]h=1\ units[/tex]

The area of the base B is equal to the area of the complete square (3 units by 3 units)  minus the area of the interior square (2 units by 2 units)

[tex]B=3^2-2^2=5\ units^2[/tex]

so the volume of the L-shaped figure is equal to

[tex]V=(5)(1)=5\ units^3[/tex]

step 2

Find the volume of the sculpture

we know that

The volume of the sculpture is equal to the volume of the L-shaped figure, multiplied by two plus the volume of two unit cubes

so

[tex]V=2(5)+2(1)=12\ units^3[/tex]

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