The work done by stretching a certain spring increases by 0.13x joules per centimeter (where x is the displacement, in centimeters, beyond the spring's natural length). How much work (in Joules) must be done in order to stretch the spring from x?

Respuesta :

Answer:

[tex]W = 0.06\cdot (x_{f}^{2}-x_{o}^{2})[/tex]

Explanation:

The work done by stretching the spring is:

[tex]W = 0.13\int\limits^{x_{f}}_{x_{o}} x\, dx[/tex]

[tex]W = 0.06\cdot (x_{f}^{2}-x_{o}^{2})[/tex]