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The equation of line AB is y = 5x + 1. Write an equation of a line parallel to line AB in slope-intercept form that contains point (4, 5).

Respuesta :

[tex]y=mx+b\\\\ 5=5\cdot4+b\\ b=5-20=-15\\\\ \boxed{y=5x-15}[/tex]
Solve is in the picture

Good luck :)
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