An 8.0 kg block is moving at 3.2 m/s. A net force of 10 N is constantly applied on the block in the direction of its movement, until it has moved 6 m. What is the approximate final velocity of the block?

Respuesta :

Answer:

5.02 m/s

Step-by-step explanation:

We are given that

Mass of block,m=8 kg

Initial velocity,u=3.2 m/s

Net force ,F=10 N

Distance,s=6 m

We have to find the approximate final velocity of the block.

We know that [tex]a=\frac{F}{m}[/tex]

Using the formula

[tex]a=\frac{10}{8}=\frac{5}{4} m/s^2[/tex]

We know that

[tex]v=\sqrt{u^2+2as}[/tex]

Using the formula

[tex]v=\sqrt{(3.2)^2+2\times \frac{5}{4}\times 6}[/tex]

[tex]v=5.02 m/s[/tex]