Answer:
W= 6.5 J
Explanation:
Given that
Spring constant ,K= 20 N/m
Initial length ,x₁ = 0.4 m
Final length , x₂ = 0.9 m
The work done is given as follows
[tex]W=\dfrac{1}{2}K(x_2^2-x_1^2)[/tex]
Now by putting the values in the above equation
[tex]W=\dfrac{1}{2}\times 20\times (0.9^2-0.4^2)\ J[/tex]
W= 6.5 J
Therefore work done will be 6.5 J.
