Light of wavelength 630 nm falls on two slits and produces an interference pattern in which the third-order bright red fringe is 45 mm from the central fringe on a screen 3.0 m away. What is the separation of the two slits?

Respuesta :

Answer:

d [tex]\frac{x}{l}[/tex] = m×  λ⇒ d = λ ×m×l / x

= 630×[tex]10^{-9}[/tex] m × 3×3m/ 45×[tex]10^{-3}[/tex] m

= 1.26×[tex]10^{-4}[/tex]m

Explanation:

the above calculation is based on Young’s double slit experiment where the two slits provide two coherent light sources which results either constructive interference or destructive interference when passing through a double slit.