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The center of a circle is located at (3,8), and the circle has a radius that is 5 units long. What is the general form of the equation for the circle?
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A. x2 + y2 - 6x - 16y + 48 = 0
B. x2 + y2 - 6x - 16y - 25 = 0
C. x2 + y2 + 6x + 16y + 48 = 0
D. x2 + y2 + 6x + 16y - 25 = 0
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ghanami

Answer:

answer: A     x²-6x+y²-16y +48=0

Step-by-step explanation:

hello :

the standard form is :   (x-3)²+(y-8)² = 25

x²-6x+9 +y²-16y+64 =25

x²-6x+y²-16y +48=0

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