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A partially discharged car battery can be modeled as a 9.0-V emf in series with an internal resistance of 0.18 Ω . Jumper cables are used to connect this battery to a fully charged battery, modeled as a 12-V emf in series with a 0.02-Ω internal resistance. How much current flows through the discharged battery? Express your answer using two significant figures. I = ________ A

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komalndm51

Answer:

The answer is 15A

Explanation:

Terminal of like polarity are connected with jumpers of negligible resistance

Kirchoff's voltage law gives

E1 -E2 - IR1 - IR2 = 0

I(R1 + R20 = E1 -E2

I= 12 -9/ 0.18 + O.2 = 15A OF CURRENT WILL FLOW THROUGH DISCHARGED BATTERY.

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