contestada

An engineer sees that the current in a coil of conducting wire goes from i1 = 0.200 A to i2 = 1.50 A in a time interval of Δt = 0.200 s. Assuming the coil's inductance is L = 3.00 mH, what is the magnitude of the average induced emf (in mV) in the coil for this time interval?

Respuesta :

Answer:

The magnitude of the average induced emf (in mV) in the coil for this time interval is 19.5 mV .

Explanation:

Induced voltage

e = L (di/dt)

e = 3* (1.5 - 0.2) / 0.20

e = 19.5 mV

Otras preguntas