Write an equation for a rational function with: Vertical asymptotes at x = -4 and x = 2 x-intercepts at x = -2 and x = -3 Horizontal asymptote at y = 3

Respuesta :

Answer:

Correct answer:  y = ( 3x² + 15x + 18) / (x² + 2x - 8)

Step-by-step explanation:

The function has vertical asymptotes at points where it is not defined.

In our case it is at  x₁ = -4 and x₂ = 2

This means that the function in the denominator has a quadratic function whose roots are (x + 4) · (x - 2) = x² + 2x - 8

The function intercepts x axis at x₀₁ = -2 and x₀₂ = -3

This means that the function in the numerator has a quadratic function whose roots are (x + 2) · (x + 3) = x² + 5x + 6

The function currently looks like this:

y = (x² + 5x + 6) / (x² + 2x - 8)

Since the function has a horizontal asymptote y = 3, this means when x strive to + - infinite or x -> + - ∞  then it is

lim x -> + - ∞ (x² + 5x + 6) / (x² + 2x - 8) = 3

This means that the function in the numerator must has term 3x² which we will get when we multiply the currently function y = (x² + 5x + 6) / (x² + 2x - 8)  by the number 3 and get :

y = 3 · (x² + 5x + 6) / (x² + 2x - 8) = (3x² + 15x + 18) / (x² + 2x - 8)

y = ( 3x² + 15x + 18) / (x² + 2x - 8)

God is with you!!!

4.30 mWhat
Which of the following is defined as the feeling evoked in the READER by apoem or work of literature?OMoodOToneOMotifMetaphor
As Rashid pursued this thinking, he wondered what would happen to his function if he started with $5 on day 0 and then earned a dollar a day.