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An empty metal can is heated to 908C and sealed. It is then placed in a room to cool to 208C. What is the pressure inside the can upon cooling? Assume that can contains air under ideal conditions. ?

Respuesta :

The pressure inside the can upon cooling is 0.4 atm.

Explanation:

Given -

Initial Temperature, T1 = 908°C = 908 + 273 K = 1181 K

Final Temperature, T2 = 208°C = 208 + 273 K = 481 K

Pressure upon cooling, P2 = ?

Using Gay Lussac's law:

P1/T1 = P2/T2

P2 = P1 X T2 / T1

P2 = 1 atm X 481 / 1181

P2 = 0.4 atm

Therefore, the pressure inside the can upon cooling is 0.4 atm.

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