contestada

Consider the following two configurations.

a. A test charge +q is brought to a point A a distance r from the center of a sphere having net charge +Q.
b. A test charge +2 q is brought to a point D a distance 2 r from the center of the sphere. Compared with the electrostatic potential at A, the electrostatic potential at B is

a.the same
b. greater
c. smaller
Compared with the electrostatic potential energy of configuration (a), the electrostatic potential energy of configuration (b) is

a. greater
b. smaller
c. the same

Respuesta :

Answer:

Explanation:

Charge on the sphere is + Q

potential at distance r ( point A )

=  k Q / r where k is 9 x 10⁹

Potential energy at A

Potential x charge

= k Q / r  x q

k Q q / r

potential at distance 2r ( point B )

= k Q / 2r

So at point B potential is less.

Electrostatic potential energy

Potential energy at B

Potential x charge

= ( k Q / 2r)  x 2q

k Q q / r

Potential energy is same  at A and B .

Otras preguntas