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A horizontal spring with a constant, k = 291 N/m, is stretched 11 cm with a 2 kg block attached to it. What is the maximum speed the block can have after it is released?

Respuesta :

Maximum speed acquired by the block is 1.32 m/s

Explanation:

Given-

spring constant, k = 291 N/m

distance, x = 11cm = 0.11m

Mass of the block, m = 2 kg

Maximum speed of the block, Vmax = ?

We know,

Period of its motion, ω = √k/m

ω = √291/2 N/mkg

ω = 12.06 rad/s

Maximum speed, Vmax = ωx

Vmax = 12.06 rad/s X 0.11m

Vmax = 1.32 m/s

Therefore, maximum speed acquired by the block is 1.32 m/s

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