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A 60 kg skier skis directly down a frictionless slope angled at 12° to the horizontal. Choose the positive direction of the x axis to be downhill along the slope. A wind force with component Fx acts on the skier. What is Fx if the magnitude of the skier's velocity is (a) constant, (b) increasing at a rate of 1.2 m/s2, and (c) increasing at a rate of 2.4 m/s2. Use g = 9.81 m/s2.

Respuesta :

Answer: a = 496.69N

b = 424.69N

c = 352.69N

Explanation: the fx = mgcos(12)-ma

At constant velocity a =0

Therefore fx = mgcos(12)=60×9.81cos(12)=496.69N

Hence a = 496.69N

b. At a = 1.2m/s2

We get fx=mgcos(12)-ma

fx=60×9.81cos(12)-60×1.2

Fx=496.69-72=424.69N

Hence b=424.69N

c. At a =2.4m/s2

Fx=mgcos(12)-ma

=60×9.81cos(12)-60×2.4

=496.69-144=352.69N

Hence c =352.69N

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