Answer:
c.[tex]5.6m/s^2[/tex]
Explanation:
Initial velocity of cheetah,u=1 m/s
Time taken by cheetah =4.8 s
Final velocity of cheetah,v=28 m/s
We have to find the acceleration of this cheetah.
We know that
Acceleration,[tex]a=\frac{v-u}{t}[/tex]
Where v=Final velocity of object
u=Initial velocity of object
t=Time taken by object
Using the formula
Then, we get
Acceleration, a=[tex]\frac{28-1}{4.8}=\frac{27}{4.8} m/s^2[/tex]
Acceleration=[tex]a=5.6 m/s^2[/tex]
Hence, the acceleration of cheetah=[tex]5.6m/s^2[/tex]
