Answer:
Explanation:
Given
If the density of liquid is twice as dense as mercury then
[tex]\rho _{liquid}=2\times \rho _{mercury}[/tex]
where [tex]\rho _{mercury}=density\ of\ mercury [/tex]
[tex]\rho _{liquid}=density\ of\ liquid[/tex]
Column of liquid w.r.t sea level is mercury is used is =760 mm of Hg
as the atmospheric Pressure is same therefore
[tex]\rho _{mercury}h_{1}g=\rho _{liquid}h_2g[/tex]
[tex]h_2=\frac{\rho _{mercury}}{\rho _{liquid}}\cdot h_1[/tex]
[tex]h_2=\frac{1}{2}\times 760=380\ mm\ of\ Hg[/tex]
