Answer: -1 and +6
Step-by-step explanation:
Given :
[tex]x^{2}[/tex] = 5x + 6
re - writing the equation , we have
[tex]x^{2}[/tex] - 5x - 6 = 0
We will look for two factors that when multiplied will give -6[tex]x^{2}[/tex] and when added will give -5. The factors are +x and -6x
Then the equation becomes :
[tex]x^{2}[/tex] -6x + x - 6 = 0
factorizing , we have
x (x-6)+1(x-6) = 0
(x-6)(x+1) = 0
Therefore :
x - 6 = 0 or x + 1 = 0
Therefore :
x = 6 or x = -1
Therefore : the rots of the equation are -1 and +6
