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A 0.2-kg block is held in place by a force that results in a 0.10-m compression of a spring beneath the block. The spring constant is 1.0 × 102 n/m. Assuming the mass of the spring is negligible compared to that of the block

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Answer:

Force on the spring will be equal to 10 N

Explanation:

We have given mass of the block m = 0.2 kg

Compression of the spring x = 0.01 m

Spring constant [tex]k=10^2N/m[/tex]

It is not given what we have to find but i think we have to find force here

We know that force on the spring is given by

[tex]F=kx=10^2\times 0.1=10N[/tex]

So the force on the spring will be 10 N

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