Option D
The correct ordered pair is (4, 1)
Solution:
Given that system of equations is:
3y = x - 1 ----- eqn 1
x - 2y = 2 ---- eqn 2
We have to use elimination method to solve the system of equations
From eqn 1,
3y = x - 1
Rearranging into standard form, we get
x - 3y = 1 ---- eqn 3
Subtract eqn 3 from eqn 2
x - 2y = 2
x - 3y = 1
(-) ---------------------
y = 1
Substitute y = 1 in eqn 1
3(1) = x - 1
3 = x - 1
x = 4
Thus the solution to given system of equations is (4, 1) Thus option D is correct
