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ABCD is a trapezoid with mid-segment (E f). If Ad=5x-11, E f=3x+7, Bc=2x+7, how many units in length is (E f) i need equation, algebra procedures, value of x, and length of (E f)

ABCD is a trapezoid with midsegment E f If Ad5x11 E f3x7 Bc2x7 how many units in length is E f i need equation algebra procedures value of x and length of E f class=

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zoeakelly

Answer:

x = 18

Step-by-step explanation:

The length of the midsection is the sum of the two bases divided by 2. Remember that the bases of a trapezoid are the two parallel sides. So that means:

((5x - 11) + (2x + 7)) /2 = 3x + 7

Simplify ((5x - 11) + (2x + 7)) /2:

(5x - 11) + (2x + 7) /2 = (5x + 2x - 11 + 7) /2 = (7x - 4) /2

Therefore:

(7x - 4) /2 = 3x + 7

Now solve this simultaneous equation:

7x - 4 = 6x + 14

7x = 6x + 18

x = 18

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