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A planar electromagnetic wave of frequency 8.5×1014Hz is propagating in a vacuum in the +y direction. At a certain point P and at a given instant, the electric field of the wave is given by E⃗ =(0.041V/m)z ^. What is the magnetic vector of the wave at the point P at that instant?

Respuesta :

Answer:

[tex]B = 1.37 \times 10^{-10} T[/tex]

Explanation:

As we know that in electromagnetic waves the two fields will induce each other

So here we have

[tex]B = \frac{E}{c}[/tex]

we have

[tex]E = 0.041 V/m[/tex]

[tex]c = 3\times 10^8 m/s[/tex]

so we have

[tex]B = \frac{0.041}{3 \times 10^8}[/tex]

[tex]B = 1.37 \times 10^{-10} T[/tex]

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