vane102002
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A Mars rover has a mass of 500 kg. The acceleration due to gravity in mars is about 3.7 m/s^2 and the coefficient of kinetic friction for the rover on the surface is 0.4. How much force must the rover’s engine exert in order to travel at a constant speed?

Respuesta :

MathPhys

Answer:

740 N

Explanation:

Friction equals normal force times coefficient of friction.  On level ground, normal force equals weight.

Constant speed means no acceleration.  Sum of the forces:

∑F = ma

F − mgμ = 0

F = mgμ

F = (500 kg) (3.7 m/s²) (0.4)

F = 740 N

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