Answer:
75.11°F
Explanation:
Given data:
Change in temperature = ?
Mass of water = 0.5 g
Heat released = 50.1 J
Specific heat of water = 4.184 j/g. °C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Q = m.c. ΔT
50.1 J = 0.5 g . 4.184 j/g. °C. ΔT
50.1 J = 2.092 j/ °C .ΔT
50.1 J / 2.092 j/ °C = ΔT
23.95 °C =ΔT
°C to °F
(23.95°C ×9/5 )+32 = 75.11°F
