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When Trevor and Brian play ping pong, the probability that Trevor will win is 0.6. If Trevor and Brian play two games of ping pong (assuming the games are independent), what is the probability that Trevor wins the first game and Brian wins the second game?

Respuesta :

JeanaShupp

Answer: 0.24

Step-by-step explanation:

Given : The probability that Trevor will win =0.6

The probability that Brian will win = 1-0.6=0.4

Since  the games are independent, so the probability that Trevor wins the first game and Brian wins the second game will be :-

[tex]\text{P(Trevor wins 1st and Brian wins 2nd )=P(Trevor wins ) x P(Brian wins)}\\\\\\=0.6\times0.4=0.24[/tex]

Hence, the probability that Trevor wins the first game and Brian wins the second game = 0.24

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