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In a Brinell hardness test, a 1500-kg load is pressed into a specimen using a 10-mm-diameter hardened steel ball. The resulting indentation has a diameter = 3.2 mm. (a) Determine the Brinell hardness number for the metal. (b) If the specimen is steel, estimate the tensile strength of the steel.

Respuesta :

Answer:

a) BHN = 181.606

b) UTS = 635.621 MPa

Explanation:

given,

Load = 1500 kg

steel ball of diameter (D) = 10 mm

resulting indentation diameter (d)= 3.2 mm

brinell hardness number

[tex]BHN = \dfrac{2P}{(\pi D)(D - \sqrt{D^2-d^2})}[/tex]

[tex]BHN = \dfrac{2\times 1500}{(\pi \times 10)(10 - \sqrt{10^2-3.2^2})}[/tex]

[tex]BHN = \dfrac{3000}{16.519}[/tex]

BHN = 181.606

b) The tensile strength of the steel

UTS = 3.5 (BHN)

UTS = 3.5  x (181.606)

UTS = 635.621 MPa

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