Answer:
The energy loss due to friction in one revolution is 4.92 J.
Explanation:
Given that,
Mass of particle = 0.358 kg
Radius = 1.66 m
Initial speed =8.19 m/s
Final speed = 6.29 m/s
We need to calculate the kinetic energy
Using formula of kinetic energy
[tex]\Delta K.E=\dfrac{1}{2}m(v_{f}^2-v_{i}^2)[/tex]
Put the value into the formula
[tex]\Delta K.E=\dfrac{1}{2}\times0.358\times(8.19^2-6.29^2)[/tex]
[tex]\Delta K.E=4.92\ J[/tex]
Hence, The energy loss due to friction in one revolution is 4.92 J.
