Answer:
Final velocity will be 6.566 m/sec
Explanation:
We have given distance s = 7.76 m
Initial speed u = 3.07 m/sec
Let m be the mass of the scallerer
Force acing down the ramp is the sinθ component of the force due to gravity and this = mg
Acceleration down the ramp = [tex]gsin26.3^{\circ}[/tex]
Speed at the bottom of the ramp can be found out using,
According to third equation of motion [tex]v^2=u^2+2as[/tex]
So [tex]v^2=3.07^2+2\times (9.8\times sin26.3)\times 7.76=43.1195[/tex]
v = 6.566 m/sec
