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In deep space( far from other objects) a 3000 of asteroid travels at 500 m/s in the Xy plane in the east north east direction. If that’s = 30 degrees and the asteroid passed through the x axis at x= 200 m, what is the angular momentum measured around the origin (1.5x10^8)k
(3x10^8)k
-(3x10^8)k
0 kg m^2/s
-(1.5x10^8)k

Respuesta :

Answer:

angular momentum = 1.5 × [tex]10^{8}[/tex] k

option 1st is correct

Explanation:

Given data

mass = 3000

velocity = 500 m/s

angle = 30 degree

x = 200 m

to find out

angular momentum

solution

we know angular momentum  about origin that is

angular momentum = x × p

angular momentum = x × m × v ×sinθ

put here all these value

angular momentum = 200 × 3000 × 500 ×sin30

angular momentum = 300000000 × 0.5

angular momentum = 150000000 k

angular momentum = 1.5 × [tex]10^{8}[/tex] k

so option 1st is correct

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