For this case we have that by definition, the arc length is given by:
[tex]Al = 2 \pi * r *\frac {a} {360}[/tex]
Where:
r: It's the radio
a: It is the angle of the sector
Then, according to the data we have:
[tex]Al = 2 \pi * 8 * \frac {45} {360}\\Al = 2 * 3.14 * 8 * \frac {45} {360}\\Al = 50.24 * \frac {45} {360}\\Al = 6.28[/tex]
Rounding we have 6.3in
Answer:
Option B
