Answer:
0.034
Step-by-step explanation:
Data:
Let the standard deviation be : [tex]\sigma = 2[/tex]
The mean be: [tex]\mu = 6[/tex]
Therefore, P (x>4) which is the probability that a person will wait for more than 4 minutes is given by:
[tex]z = \frac{X- \mu }{\sigma }[/tex]
= [tex]\frac{4-6}{2} \\= -1[/tex]
Therefore,
P(x > 4) = P (z > -1)
= P (z < -1)
From the z-tables, we find 0.034
