Respuesta :

Answer:

The transformation that follows are:

  • Shift 2 units up.
  • Shift 5 units to the left.
  • Vertical shrink by a factor of 2.

Step-by-step explanation:

We are given a graph as:

     [tex]y= (x-1)^2-3[/tex]

Now, this graph is translated to get a new graph as:

       [tex]y=\dfrac{1}{2}(x+4)^2[/tex]

  • First the graph of the original function is shifted 3 units up.

Since, the translation of the type:

f(x) to f(x)+k is a shift k units up or k units down depending on whether k is positive or negative respectively.

[tex]y=(x-1)^2-3+3\\\\i.e.\\\\y=(x-1)^2[/tex]

  • Now, this graph is then shifted 5 units left.

since the translation of the type f(x) to f(x+k) is a shift of  the function f(x) k units to the left or k units to the right depending on k whether k is positive or negative respectively.

Here,

[tex]y=(x-1+5)^2\\\\i.e.\\\\y=(x+4)^2[/tex]

  • Now, this graph is then vertically shrink by a factor of 2.

Because the transformation of the type:

         f(x) to kf(x) is a vertical stretch if k>1

and vertical shrink if 0<k<1.

i.e.

[tex]y=\dfrac{1}{2}(x+4)^2\\\\i.e.\\\\k=\dfrac{1}{2}<1[/tex]

To solve the problem we must know about the equation of a parabola.

When the graph of y= (x-1)^2-3 is transformed to produce the graph of y= 1/2(x+4)^2, the vertex of the parabola shifts from (1,-3) to  (-4,0) and the graph of the parabola gets wider as well by a factor of 2.

What is the Equation of a parabola?

[tex]y = a(x-h)^2 + k[/tex]

where,

(h, k) are the coordinates of the vertex of the parabola in form (x, y);

a defines how narrower is the parabola, If the value of a is more the graph will be narrower, and the "-" or "+" that the parabola will open up or down.

Given to us

[tex]y= (x-1)^2-3[/tex]

[tex]y= \dfrac{1}{2}(x+4)^2[/tex]

As we have revised the concept of a parabola, if we compare the two given equations with the general equation of a parabola,

In equation 1,

[tex]y= (x-1)^2-3[/tex]

[tex]y = a(x-h)^2 + k[/tex]

(h,k) = (1,-3)

a = +1

In equation 2,

[tex]y= \dfrac{1}{2}(x+4)^2[/tex]

[tex]y = a(x-h)^2 + k[/tex]

(h,k) = (-4,0)

a = +1/2

  • As we can see in the above comparison the coordinate of the vertex of the parabola changes from  (1,-3) to  (-4,0).
  • Also, the value of 'a' changes from 1 to 1/2, therefore, the graph gets wider by a factor of 2.

The above conclusions can be seen in the graph plotted below.

Hence, when the graph of y= (x-1)^2-3 is transformed to produce the graph of y= 1/2(x+4)^2, the vertex of the parabola shifts from (1,-3) to  (-4,0) and the graph of the parabola gets wider as well by a factor of 2.

Learn more about Parabola:

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