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Use Plank’s constant, 6.626 × 10-34, to solve the following:
What is the amount of energy carried by a photon that has a frequency of 5.71 × 1014Hz?

Question 15 options:

525 nm

3.78 × 10-19 J

1.14 × 10-8 J

8.62 × 1047 J/s

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Respuesta :

Answer:

B. [tex]3.78 \times 10^{-19}[/tex] J

Explanation:

Energy (E) = Planck's constant (h) × Frequency (ν)

1 Hertz = 1 [tex]s^{-1}[/tex]  

So Hertz and [tex]s^{-1}[/tex] are equal

[tex]E=6.626 \times 10^{-34} Js \times 5.71 \times 10^{14} s^{-1}[/tex]

(s and [tex]s^{-1}[/tex] gets cancel as both are in the numerator leaving behind Joules)

[tex]=37.8 \times 10^{-20} J[/tex]

(Moving the decimal point to the left one place power of 10 increases from -20 to - 19)

[tex]= 3.78 \times 10^{-19}[/tex] J (Answer)

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