Answer:
D. 5.2Ω
Explanation:
Resistors in parallel have a net resistance of:
R = (1/R₁ + 1/R₂)⁻¹
The 2.0Ω resistor and the 3.0Ω resistor are in parallel, so the combination has a net resistance of:
R = (1/2.0 + 1/3.0)⁻¹
R = 1.2Ω
Resistors in series of a net resistance of:
R = R₁ + R₂
The 4.0Ω resistor is in series with the 2.0Ω/3.0Ω combination. So the net resistance of all three is:
R = 1.2Ω + 4.0Ω
R = 5.2Ω
