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The reaction of sodium peroxide and water produces sodium hydroxide and oxygen gas. The following balanced chemical equation represents the reaction.

2 Na^2O^2(s) + 2 H2O(l) → 4 NaOH(s) + O^2(g)

If 15.7 moles of sodium hydroxide are produced, how many moles of O2 will be made?

Respuesta :

superman1987

Answer:

3.925 mol.

Explanation:

  • From the balanced equation:

2 Na₂O₂(s) + 2 H₂O(l) → 4 NaOH(s) + O₂(g) ,

It is clear that 2 moles of Na₂O₂ react with 2 moles of H₂O to produce 4 moles of NaOH and 1 mole of O₂ .

Using cross multiplication:

4 moles of NaOH produced with → 1 mole of O₂ .

15.7 moles of NaOH produced with → ??? mole of O₂ .

∴ The no. of moles of O₂ made = (1 mole)(15.7 mole)/(4 mole) =  3.925 mol.

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