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Determine the mass of the load hanging on the spring with a stiffness of 200 N / m if the extension of the spring is 0.5 cm

Respuesta :

P. E=mgh

P. E=200

200=m x 10 X 0.005

200=m x 0.05

200/0.05=m

4000Kg=m

Hope it helps.......

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