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What is the point-slope form of a line that has a slope of 3 and passes through the point (–1, 4)?

y – (–1) = 5(x – 4)

4 – y1 = 3(–1 – x1)

y – 3 = –1[(x – (–4)]

y – 4 = 3[(x – (–1)]

Respuesta :

Answer:

D

Step-by-step explanation:

The equation of a line in point-  slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

here m = 3 and (a, b) = (- 1, 4), hence

y - 4 = 3( x - (- 1)) which simplifies to

y - 4 = 3(x + 1)


saathvi19

Answer:

D. y-4=3[(x-(-4)]

Step-by-step explanation:

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