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Triangle TUV is graphed on the coordinate plane below.


The figure is rotated 270°counterclockwise using the origin as the center of rotation. Where is point V’?
(1, –3)
(3, –1)
(–3, 1)
(–1, 3)

Triangle TUV is graphed on the coordinate plane below The figure is rotated 270counterclockwise using the origin as the center of rotation Where is point V 1 3 class=

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darwincortez659

Answer: point V' is located at (3,-1)

Answer:

The correct option is 2.

Step-by-step explanation:

If a figure rotated 270°counterclockwise with origin as the center of rotation, then

[tex](x,y)\rightarrow (y,-x)[/tex]

From the given graph it is clear that the coordinates of V are (1,3), the coordinates of V' are

[tex]V(1,3)\rightarrow V'(3,-1)[/tex]

The coordinates of V' are (3,-1).

Therefore the correct option is 2.

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