Answer:
Diameter of the circle is [tex]8\sqrt{2}[/tex] units
Step-by-step explanation:
It is given that the vertices of the square fall on the circle.
So, the diagonal of the square is the diameter of the circle.
Also, the diagonal and the two sides of the square form a right angled triangle.
By Pythogoras theorem,
[tex]hypotenuse^{2} =side^{2} +side^{2}[/tex]
= [tex]8^{2} +8^{2}[/tex]
= [tex]2(8^{2} )[/tex]
[tex]hypotenuse=8\sqrt{2}[/tex] units
Hence, the diameter of the circle is [tex]8\sqrt{2}[/tex] units
