If the Kelvin temperature of a gas is tripled and the volume if doubled, the new pressure will be ___. A. 3/2 the original pressure B. 1/6 the original pressure C. 5 times the original pressure D. 2/3 the original pressure
The answer is 3/2 the original pressure. The concept behind
this is the ideal gas law wherein it states that Pressure (P) times volume(V)
is equal to number of moles (n) times ideal gas constant (R ) times temperature
(T). Since you’re trying to calculate for the pressure you use P=nRT/V. Input 3
to Temperature and 2 to volume. You’ll get a pressure of 3/2 which is 3/2 times
the original pressure.
