kaytown06 kaytown06

24-08-2018
Mathematics

contestada

ALGEBRA 1, SEM. 2; PLEASE SHOW WORK
f(x)=x2+4x+7 in vertex form

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konrad509 konrad509

24-08-2018

[tex] f(x)=x^2+4x+7 \\
f(x)=x^2+4x+4+3\\
f(x)=(x+2)^2+3 [/tex]

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choixongdong choixongdong

24-08-2018

f(x) = x^2 + 4x + 7

f(x) = x^2 + 4x + 4 + 3

f(x) = (x + 2)^2 + 3

Vertex (h, k) where h = - 2 and k = 3

So vertex (-2 , 3)

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