Respuesta :

gmany
[tex]F=\dfrac{9}{5}C+32\\\\\text{substitute F=45}\\\\\dfrac{9}{5}C+32=45\ \ \ \ |-32\\\\\dfrac{9}{5}C=13\ \ \ \ |\cdot5\\\\9C=65\ \ \ \ |:9\\\\C=\dfrac{65}{9}\\\\C=7.2222....\\\\C\approx7\\\\\text{Answer:}\ 45^oF\approx7^oC\to B.[/tex]
(F - 32)9 = C/5

(45 - 32) / 9 = C/5
9C = 5*13
C = 65/9 = 7.2 degrees C to nearest tenth.

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