The equation h(t)=−16 t 2 +19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff. What is the initial velocity when the rock is thrown? Enter your answer in the box.
For this case we have an equation of the form: h (t) = (1/2) * a * t ^ 2 + vo * t + h0 Where, a: acceleration vo: initial speed h0: initial height t: time We have then that the equations: h (t) = - 16t ^ 2 + 19t + 110 Therefore, the initial velocity is given by: vo = 19 feet / s Answer: The initial velocity when the rock is thrown is: vo = 19 feet / s
